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A `CE` amplifier is designed with a transistor having `alpha =0.99`. Input impedance is `1 k Omega` and load is `10 k Omega`. Voltage gain will be :

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A `CE` amplifier is designed with a transistor having `alpha =0.99`. Input impedance is `1 k Omega` and load is `10 k Omega`. Voltage gain will be :
A. `9900`
B. `99000`
C. `99`
D. `990`
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Correct Answer - D
`beta =(alpha)/(1-alpha)` and `A_(v)=beta xx(R_(AC))/(R_("in"))`.
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