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In a transistor amplifier `beta = 62, R_(L) = 5000 Omega` and internal resistance of the transistor is `500 Omega`. Its power amplification will be.

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In a transistor amplifier `beta = 62, R_(L) = 5000 Omega` and internal resistance of the transistor is `500 Omega`. Its power amplification will be.
A. `25580`
B. `33760`
C. `38440`
D. `55760`
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1 Answer

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by (88.6k points)
Correct Answer - C
`A_(P)=beta^(2)(R_(L))/(R_(i))`.
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