Question

Two solutions of a substances (non electrolyte) are mixed in the following manner. 480 ml of `1.5M` first solution `+520 mL` of `1.2M` second solution. What is the molarity of the final mixture?
A. `1.50M`
B. `1.20M`
C. `2.70M`
D. `1.344M`

Answer 1

Correct Answer - D
`M = (M_(1)U_(1)+M_(2)U_(2))/(V_(f)) = (M_(1)U_(1)+M_(2)U_(2))/(V_(1)+V_(2))`
`= (1.5 xx 0.48 +1.2 xx 0.52)/(1)`
`= 0.72 +0.624`
`= 1.344 M`