Question

In YDSE, the two slits are separated by 0.1 mm and they are
0.5 m from the screen. The wavelength of light used is 5000 Å. Find the distance
between 7th maxima and 11 th mimima on the upper side of screen.

Answer 1

Here, `d=0.1 mm =10^(-4)m`,
`D=0.5m, lambda=5000 Å = 5.0xx10^(-7)m`
`:. Delta x=(X_(11))_("dark")-(X_(7))_("bright")= ((2xx11-1)lambdaD)/(2d)-(7lambdaD)/(d)`
`Delta x=(7lambdaD)/(2d)= (7xx5xx10^(-7))/(2xx10^(-4))`
`=8.75xx10^(-3)m`
`= 8.75 mm`