Correct Answer - D
Let nth minima of 400 nm coincides with mth minima of 560 nm, then
`(2n - 1) ((400)/(2)) = (2m - 1) ((560)/(2))`
or `(2n-1)/(2m-1) = (7)/(5) = (14)/(10) =` …
i.e., `4^(th)` minima of 400 nm coincides with `3^(rd)` minima of 560 nm.
Location of this minima is,
`Y_(1) = ((2xx4-1)(100)(400xx10^(-6)))/(2xx0.4) = 14 nm`
Next `11^(th)` minima of 400 nm coincides with `8^(th)` minima of 560 nm, then
`(2n-1) ((400)/(2)) = (2m - 1) ((560)/(2))`
or `(2n-1)/(2m-1) = (7)/(5) = (14)/(10)= ` ...
i.e., `11^(th)` minima of 400 nm coincides with `8^(th)` minima of 560 nm.
Location of this minima is, `+Y_(2)` =
`((2xx11-1)(100)(400xx10^(-6)))/(2xx0.1) = 42mm`
Required distance `= Y_(2)-Y_(1) = 28 mm`
Hence, the correct optical is (D).