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Propene is allowed to react with `HBr` in the presence of benzoyl peroxide and the product is subsequently heated with aqueous `KOH`. The final product obtained is
A. propane -`1-ol`
B. propane-`2-ol`
C. propane-`1,2`-diol
D. propane-`1,3`-diol

1 Answer

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Best answer
Correct Answer - A
`CH_(3)CH = CH_(2) underset((C_(6)H_(5)CO)_(2)O_(2)) overset(HBr)rarr CH_(3)CH_(2)CH_(2)Br overset(aq.KOH)rarrCH_(3)underset("Propan-1-ol")(CH_(2)OH)`
First step involves anti-Markovnikov addition while the second step involves hydrolysis of halide.

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