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1.2 L of 0.4 M HCl solution can be completely neutralized by

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1.2 L of 0.4 M HCl solution can be completely neutralized by
A. 600 mL of 1.2 M NaOH solution
B. 800 mL of 0.2 M NaOH solution
C. 19.2 g of solid NaOH
D. 4.8 mole of NaOH
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Correct Answer - C
Moles of HCl`=(1200xx0.4)/(1000)=0.48`
Moles of `NaOH=(19.2)/(40)=0.48`
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