Question

Two resistor of resistance `R_(1)=(6+-0.09)Omega` and `R_(2)=(3+-0.09)Omega` are connected in parallel the equivalent resistance R with error (in `Omega)`
A. `R=(2+-0.04)`
B. `R=(2+-0.05)`
C. `R=(9+-0.18)`
D. `R=(2+-0.18)`

Answer 1

Correct Answer - B
`(1)/(R)=(1)/(R_(1))+(1)/(R_(2))" "thereforeR=2Omega`
`(dR)/(R^(2))=(dR_(1))/(R_(1)^(2))+(dR_(2))/(R_(2)^(2))impliesdR=0.05Omega`
`thereforeR=(2+-0.05)Omega`.