Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+2 votes
67.6k views
in Mathematics by (40.8k points)

Let X = {1, 2, 3, 4, 5}.The number of different ordered pairs (Y , Z) that can formed such that Y  X, Z ⊆ X and y   Z is empty, is

(a) 52 

(b) 35 

(c) 25 

(d) 53

by (10 points)
+1
Thanks so much bro ...u answered it in perfect way ....other sites just telling with permutations which does not show any logic in it

1 Answer

+4 votes
by (45.0k points)
selected by
 
Best answer

Correct option (b) 35 

Explanation:

Let us explain anyone of the above 6 rows say third row. In third row ,

Number of elements in Y = 2

Number of ways to select Y = 5C2 ways

Because any 2 elements of X can be part of y.

Now, if Y contains any 2 elements, then these 2 elements cannot be used in any way to construct Z because we want Y U Z = ϕ. And from the remaining 3 elements which are not present in Y, 23 subsets can be made each of which can be equal lo Z and still Y ⋂ Z = ϕ will be true.  Hence, total number of ways to construct sets Y and Z such that Y ⋂ Z = ϕ

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...