Correct Answer - A
The `OH` group in alcohols contains a `H`bonded to a highly electronegative oxygen atom. Therefore, it is capable of forming intermoecular `H-`bond as shown below:
`R-underset(H)underset(|)overset(delta-)(O)….overset(delta+)(H)-underset(delta-)overset(R)overset(|)(O)....overset(delta+)(H)-underset(R )underset(|)overset(delta-)(O)....overset(delta+)(H)-overset(R )overset(|)(O)`
It is due to the presence of intermolecular hydrogen bonding that alcohols have higher boiling points corresponding to ether which are incapable of exhibiting intermolecular `H` bonding.