The element with the electronic configuration `[Ze]^(54) 4f^(14)5d^(1)6S^(2)` is a

After achieving `4f^(14),5d^(0),6s^(2)` configuration , the next electron goes to `5d` and this is the case of `Lu(Z=71)` which is the last element of lanthanoid series
Therefore , (C ) option is correct

The element with the electronic configuration `[Ze]^(54) 4f^(14)5d^(1)6S^(2)` is a

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