Correct Answer - B
(A)` Cu^(+)[Ar]^(18)3d^(10),Son=0,Zn^(2+)[Ar]^(18)3d^(10),So n=0,Sc^(3+)[Ar]^(18)3d^(0),So n=0`
(N ) (B)` Mn^(2+)[Ar]^(18)3d^(10),Son=5,Fe^(3+)[Ar]^(18)3d^(5),So n=5,Ni^(2+)[Ar]^(18)3d^(8),So n=2`
(C )` Cr^(2+)[Ar]^(18)3d^(4),Son=4,Mn^(3+)[Ar]^(18)3d^(4),So n=4,Sc^(3+)[Ar]^(18)3d^(0),So n=0`
(D ) ` Cu^(2+)[Ar]^(18)3d^(9),Son=1,Ni^(2+)[Ar]^(18)3d^(8),So n=2,Ti^(4+)[Ar]^(18)3d^(0),So n=0`