Correct Answer - 3
(3) Cerium can also show the oxidation state of `+4` in solution as it leads to a noble gas configuration, from `[Xe]^(54) 4f^(1) 5d^(1) 6s^(2)` to `[Xe]^(54)`, after losing four electrons. It is only `Ce^(4+)` which exits in solution among the lanthanides.