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2.5 litre of 1 M NaOH solution are mixed with another 3 litre of 0.5 M NaOH solution Then the molarity of the resulting
A. 0.80 M
B. 1.0 M
C. 0.73 M
D. 0.50 M

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Correct Answer - 3
Molarity of the resulting solution `=("Total moles")/("Total volume")`
`=(M_(1)V_(1)+M_(2)V_(2))/(V_(1)+V_(2))`
`=((1 M)(2.5 L)+(0.5 M)(3 L))/((2.5 L+3.0 L))`
`=0.727 M=0.73 M`

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