Correct Answer - C
This is the characteristic of a first oeder reaction as shown below
`k=(2.303)/(t)log(P_(0))/(p_(t))`
log `(P_(0))/(P_(t))=(k)/(2.303)t`
log `P_(0)-logp_(t)-(k)/(2.303)t`
or `{:(logp_(t)=,logp_(0),-,(k)/(2.303),t),(overset(uarr)(y),overset(uarr)(b),overset(uarr)(m),overset(uarr)(x)):}`
This equation is of the form `y=mx+b` . Thus, if we graph log `p_(t)1 versus time, we obtain a straigh line having a negative slope equal to `-k//2.303` and an intercept on `y-`axis equal to log `p_(0)` Thus, form the value of the slope, we can determine the rate constant:
`k=(-(slope))/(2.303)`