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A uniform disc of mass m and radius `R` is released gentiy on a horizontal rough surface. Such that centre of the disc has velocity `V_(0)` towards right and angular velocity `omega_(0)` (anticlockwise) as shown.
image
Disc will certainly come back to its intial position if
A. `omega_(0)R gt2V_(0)`
B. `omega_(0)R=2V_(0)`
C. `omega_(0)Rlt2V_(0)`
D. It is impossible

1 Answer

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Best answer
Correct Answer - A
A uniform disc …………
image
w.r.t. point `P` net angular momentum must be anticlockwise
`(mR^(2))/(2)omega_(0)gt mV_(0)R`
`omega_(0)R gt 2V_(0)`

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