Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.1k views
in Chemistry by (90.6k points)
closed by
The hybridization states of the nitrogen atom in pyridine piperidine and pyrrole are respectively
A. `sp^(2),sp^(3)andsp^(2)`
B. `sp^(2),sp^(2)andsp^(2)`
C. `sp^(3),sp^(3)andsp^(3)`
D. `sp^(2),sp^(3)andsp^(3)`

1 Answer

0 votes
by (88.6k points)
selected by
 
Best answer
Correct Answer - A
In pyridine the steric number of `N` is three as it bonded to two C atoms and carries one lone pair thus `sp^(2)` hybridized In piperdine the steric number of `N` is four as it is boned to two C atoms one `H` atom and carries one lone pair thus `sp^(3)` hybridized In pyrrole the steric number of N atom is three as its lone pair of electrons is involved in resonane with the benzene ring thus `sp^(2)` hybridised
image
image
image .

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...