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The producet of the reaction of alcoholic silver nitrite with ethyl bromide is :
A. Nitroethane
B. Nitroethane and ethyl nitrite
C. Ethyl nitrite
D. Ethane

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Correct Answer - A
(1) `C_(2)H_(5)+Ag-O-N=Orarrunderset("Nitre ethane")(C_(2)H_(5)-N)overset(O)underset(O)+AgBr^(-)`
`Ag-O-N = 0` is a covalent compound. Therefore, attack to nuclephile occurs through Nitrogen atom. Hence, nitroethane is formed.

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