Question

Calculate the pH of a solution of given mixtures;

(a) (4g CH₃COOH + 6g CH₃COONa) in 100 mL of mixture; K_a for CH₃COOH = 1.8 x 10^-5

(b) 5 mL of 0.1 MA/OH + 250 mL of 0.1 M MCI, Ka for MOH = 1.8 x 10^-5

(c) (0.25 mole of CH₃COOH + 0.35 mole of CH₃COONa) in 500 mL mixture;  Ka for CH₃COOH = 3.6 x 10^-4

Answer 1

pOH = 14 - pOH = 7.5563