Correct Answer - 3
In `[Cr(CN)_(5)]^(3-),Cr`is present as `Cr^(3+)`.
`Cr^(3+)=[Ar]3d^(3),4s^(0)`
`[Cr(CN)_(6)]^(3-)=[Ar]`
Since, this complex has three unpaired electrons, excitation of electrons is possible and thus, it is expected that this complex will absorb visible light.