Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.8k views
in Physics by (88.1k points)
closed by
A particle moves according to the law, `x=acos(pit//2).` . What is the distance covered by it in time interval `t=0` to `t=3` second.
A. `2a`
B. `3a`
C. `4a`
D. `a`

1 Answer

0 votes
by (89.4k points)
selected by
 
Best answer
Correct Answer - B
Comparing the given equation with `x = a cos omegat`
`:. omega = (pi)/(2)` or `(2 pi)/(T) = (pi)/(2) :. T = 4 sec`
The given time `t = 3` sec is really `(3T)/(4)`
`:.` distance covered will be 3 a

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...