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`CrO_(4)^(2-)` (yellow) changes to `Cr_(2)O_(7)^(2-)(`orange ) in `pH=y` . Hence `x` and `y` are `:`

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`CrO_(4)^(2-)` (yellow) changes to `Cr_(2)O_(7)^(2-)(`orange ) in `pH=y` . Hence `x` and `y` are `:`
A. `6,8`
B. `6,5`
C. `8,6`
D. `7,7`
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`2CrO_(4)^(2-)+2H^(+)rarrCr_(2)O_(7)^(2)+H_(2)O`
`Cr_(2)O_(7)^(2-)+2OHrarr2CrO_(4)^(2-)+H_(2)O`
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