Correct Answer - B
Initial momentum of surface
`P_(i) = (E)/(C)`
where c = velocity of light (constant). Since, the surface is perfectly reflecting so the same momentum will be reflected completely Final momentum
`P_(i)=(E)/(C)`(negative value)
`:.` Change in momentum
`Delta_(p) = p_(f)-P_(i) = -(E)/(C)-(E)/(C) = -(2E)/(C)`
Thus, momentum transferred to the surface is
`Delta_(p)=|Delta_(p)|=(2E)/(C)`.
