Correct Answer - C
Energy of the photon
`E = (hc)/(lamda) = (1240)/(97.5) =12.75 eV`
This energy is equal to energy gap between `n =1(-13.6)` and `n = 4(-0.85)`. So by this energy. The electron will excite form n =1 to n = 4. When the electron will fall back. number of spectral lines emitted.
`=(n(n-1))/(2)=((4)(4-1))/(2)=6`.