Correct Answer - C
`I_(1_("rms")) =(E_("rms"))/(sqrt(X_(C)^(2)+R_(1)^(2)))=(130)/(13) =10A`
`i_(2_("rms")) =(E_("rms"))/(sqrt(X_(L)^(2)+R_(2)^(2)))=13 A`
Power dissipated
`=i_(1_("rms"))^(2)R_(1)+R_(2_("rms"))^(2)R_(2)=10^(2)xx5+13^(2)xx6`
=Power delivered by battery
`= 500 + 169 xx 6 = 1514` watt.