Correct Answer - A
Oxalic acid dihydrate `H_(2)C_(2)O_(4).2H_(2)O " mw = 126`
It is a dibasic acid, hence equivalent weight `= 63`
`rArr` Normality `= (6.3)/(63) xx (1000)/(250) = 0.4 N`
`rArr N_(1)V_(1) = N_(2)V_(2)`
`rArr 0.1 xx V_(1) = 0.4 xx 10`
Hence, `V_(1) = 40 mL`