Oxidation number of `P` in `Ba(H_(2)PO_(2))_(2)` is

Correct Answer - C
In `Ba(H_(2)PO_(2))_(2)`, oxidation number of `Ba` is `+2`. Therefore,
`H_(2)PO_(2)^(2-) : 2 xx (-1) + x +2 xx (-2) = -1`
`rArr " " x = +1`

Oxidation number of `P` in `Ba(H_(2)PO_(2))_(2)` is

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