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When acetamide reacts with `Br_(2)` in presence of `NaOH`, there is a formation of `:`

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When acetamide reacts with `Br_(2)` in presence of `NaOH`, there is a formation of `:`
A. `CH_(3)NH_(2)`
B. `CH_(3)CN`
C. `CH_(3)CH_(2)OH`
D. `CH_(3)CHO`
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`CH_(3)-underset(underset(O)(||))(C)-NH_(2)underset("Hofmannbromamide")overset(Br_(2)+NaOH)rarrCH_(3)-NH_(2)`
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