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Atoms `._(7)X^(A),._(8)Y^(B)` and `._(9)Z^(17)` are such that `._(8)Y` is an isobar of `._(7)X` and atom `._(9)Z^(17)` is isotone of `._(8)Y`. Mass no. of `X` and no of neutrons in `Y` are respectively `:`
A. `8,8`
B. `17,7`
C. `9,8`
D. `16,8`

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Correct Answer - 4
Isotones have same no. of neutrons.
`17-9=B-8`
`B=16`
Isobars have same mass no
`A=B=16`
no. of neutrons `16-8=8`

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