Correct Answer - 3
`{:(Cu^(3+)+2e^(-)rarr Cu,,E^(@)=0.337V,,DeltaG^(@)=-2Fxx0.337),(Cu^(@+)+e^(-)rarrCu^(+),,E^(@)=0.153V,,DeltaG^(@)=-1Fxx0.153),(Cu^(@+)+2e^(-)rarr Cu,,E_(1)^(@)=0.337V,,DeltaG_(1)^(@)=-2Fxx0.337),(Cu^(+)rarrC^(@+)+e^(-),,E_(2)^(@)=0.153V,,DeltaG_(1)^(@)=1xxFxx0.153),(bar(Cu^(+)+e^(-) rarr Cu),,E_(3)^(@)=?,,DeltaG_(3)^(@)=-1xxFxxE_(3)^(@)):}`
`DeltaG_(3)^(@)=DeltaG_(1)^(@)+DeltaG_(2)^(@)`
`-1xxE_(3)^(@)=-2Fxx0.337+Fxx0.153`
`E_(3)^(@)=2xx0.337-0.153=0.521V`.