Question

The specific rate constant for the decomposition of formic acid is 5.5 x 10^-4 sec^-1 at 413 K. Calculate the specific rate constant at 458 K if the energy of activation is 2.37 x 10⁴ cal mol^-1.

Answer 1

Given :

K₂ = ?, K₁ = 5.5 x 10^-4, R = 1.987 cal, T₁ = 413 K, T₂ = 458 K, E_a = 2.37 x 10⁴ cal mol^-1