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Locus of the point which divides double ordinate of the ellipse (x^2/a^2)/+(y^2/b^2)

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Locus of the point which divides double ordinate of the ellipse (x2/a2)/+(y2/b2) = 1 in the ratio 1 :2 internally, is

(a) (x2/a2)-(9y2/b2) = 1/9

(b) (x2/a2)+(9y2/b2) = 1

(c) (9x2/a2)+(9y2/b2) = 1

(d) None of these

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1 Answer

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Best answer

Correct Option (b) (x2/a2)+(9y2/b2) = 1

Explanation:

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