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Let tan^-1 y = tan^-1 x + tan^-1 (2x/1-x^2) where |x| < 1/ √3. Then a value of y is

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Let tan-1 y = tan-1 x + tan-1 (2x/1-x2) where |x| < 1/ √3. Then a value of y is

(a) 3x - x3/ 1-3x2

(b) 3x + x3 / 1- 3x2

(c) 3x - x3/ 1+ 3x2

(d) 3x + x3/ 1+3x2 

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The correct option is (a) 3x - x3/ 1-3x2.

Explanation:

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