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A `20.0mL` sample of `CuSO_(4)` solution was evaporated to dryness, leaving `0.967g` of residue. What was the molarity of the original solution ? `(Cu=63.5)`
A. `48.4M`
B. `0.0207M`
C. `0.0484M`
D. `0.303M`

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Correct Answer - D
Molarity `=(0.967//159.5)/(20//1000) {"Mol" wt. of underset(159.5)(CuSO_(4))}`
`=0.303M`

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