Question

The time period of revolution in the `3^(rd)` orbit of `Li^(2+)` ion is x sec. The time period of revolution in the `2^(nd)` orbit of `He^(+) ion, should be
A. x sec
B. `3/2 x sec`
C. `2/3 x sec`
D. `8/27 x sec`

Answer 1

Correct Answer - 3
`Talpha (n^(3))/(Z^(2))`
`x/y=9/3xx(2^(2))/(2^(3))`
`y=2/3 x sec`