Correct Answer - B
The magnetic flux that links the larger loop with the smaller loop of side `l(lltltL)` is `f_(12)=Bl^(2)=(2sqrt(2)mu_(0)Il^(2))/(piL)`
`therefore` Mutual inductance `M_(12)=(phi_(12))/(I)=(2sqrt(2)mu_(0))/(pi)((l^(2))/(L))`
`i.eM_(12)prop(l^(2))/(L)`
`therefore (b)`