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In the circuit shown in the figure, if both the lamps `L_(1)` and `L_(2)` are identical
image
A. Their brightness will be same
B. `L_(2)` will be brighter than `L_(1)`
C. As frequency of supply voltage is increased brightness of `L_(1)` will increase and that of `L_(2)` will decrease
D. Only `L_(2)` will glow because the capacitor has infinite resistance.

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Correct Answer - B::C
`X_(C)=(1)/(omegaC)=(1)/(2pi(50)(500xx10^(-6)))=(20)/(pi)Omega`
`X=omegaL=2pi(50)(10xx10^(-3))=piOmega`
`X_(C)gtX_(L)`

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