Correct Answer - A
The circuit is in resonance `(becauseV_(1)=V_(2))`
`R=(V)/(l)=(120sqrt(2))/(10)=10sqrt(2)Omega`
Q factor = `(1)/(R )sqrt((L)/(C))=(1)/(10sqrt(2))xxsqrt((2xx10^(-3))/(0.8xx10^(-6)))=(1)/(10sqrt(2))xxsqrt((2xx10^(4))/(8))=(50)/(10sqrt(2))=(5)/(sqrt(2))`