Correct Answer - `(i) (1)/(10) (ii) (1)/(5)`
`P(E_(1) cap E_(2))=P(E_(1))+P(E_(2))-P(E_(1) cup E_(2))`
`=(1)/(2)+p-(3)/(5)=(10 p-1)/(10)`
यदि घटनायें परस्पर अपवर्जी है तो `P(E_(1) cap E_(2))=0`
`rArr" "(10-1)/(10)=0 rArr p= (1)/(10)`
यदि घटनायें स्वतन्त्र है तब
`P(E_(1) cap E_(2))=P(E_(1)) cdot P(E_(2))=(10 p-1)/(10)=(1)/(2)xxp, p` के लिए हल करो |