Correct Answer - C
माना `OA=10hati+3hatj`
`OB=12hati-5hatj`
`OB=mhati+11hatj`
`therefore` A,B C
`AB=lambdaBC`
`Rightarrow (OB-OA)=lambda(OC-OB)`
`Rightarrow (2hati-8hatj)=lambda{(m-12)hati+16hatj}`
`lambda (m-12)=2.....(i)`
`16lambda=-8Rightarrowlambda=-(1)/(2)`
`-(1)/(2)(m-12)=2 Rightarrow m-12=-4 Rightarrow m=8`
