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The plate voltage of a triode is increased from 225 V to 250 V, the grid voltage is changed from 4 to `-4.7V` to maintain plate current constant. The amplification factor of the tube is
A. 35.7
B. 2
C. 70
D. 20

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Correct Answer - A
`V_(p_(1))=225V, V_(p_(2))=250V, V_(g_(1))=-4V`
`V_(g_(2)) = -4.7V`
`mu=((DeltaV_(p))/(DeltaV_(g)))_(l_(p))=(25)/(0.7) = 35.7`

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