We determine the speed required at `D` so that the block falls into the hole at `E` by following a parbolic trajectory.
`v_(d)=`speed at `D`
`v_(d)=sqrt(8gd)`
Applying conservation of energy for motion from `A` to `D`
`(1)/(2)kdelta^(2)=mu_(k)mgd+mgd+(1)/(2)m(8gd) rArr delta=sqrt((2mgd)/(k)(mu_(K)+5))`