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The entire network shown here, has uniform wire having resistance per unit length as `1Omega//m`. It is placed in a uniform but time varying magnetic field `vecB`(directed into the plane). If the strength of the magnetic field is increasing at `1T//s`, the ratio `I_(1)//I_(2)` equals
image
A. `2`
B. `4`
C. `1//3`
D. `1//6`

1 Answer

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Best answer
`3(I_(1)+I_(2))+I_(1)=1`
`rArr 4I_(1)+3I_(2)=1`…..(`i`)
`2I_(2)-I_(1)=1//2`
`rArr-2I_(1)+4I_(2)=I`……(`ii`)
By solving equations (`i`) and (`ii`)
`(I_(1))/(I_(2))=(1)/(6)`
image

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