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When 10.6 g of a nonvolatile substance is dissolved in 740 f of ether, its boiling point is raised `0.284^(@)"C"`. What is the molecular weight of the substance? Molal boiling point costant of ether is `2.11^(@)"C kg"//"mol"`.

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Correct Answer - `"106 g/mol"`
Solute-B, Ether-A
`Delta"T"_("b")="K"_("b")xx("w"_("B")xx1000)/("m"_("B")xx740)`
`0.284=211xx(10.6xx1000)/("m"_("B")xx740)`
`"m"_("B")=106"gm mol"^(-1)`

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