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The conductivity of 0.1 n NaOH solution is 0.022 S`cm^(-1)`.When equal volume of 0.1 N HCl solution is added, the conductivity of resultant solution is decreased to 0.0055 S `cm^(-1)` . The equivalent conductivity in `Scm^(2)equi^(-1)` of NaCl solution is :
A. `0.0055`
B. `0.11`
C. 110
D. 55

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Correct Answer - C
Normality of resulatant solution of `=(0.1xxV)/(VxxV)=0.05N`
`Lambda_(eq)=1xx(0.0055)/(0.05)="110 S cm"^(2)eq^(-1)`

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