Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.2k views
in Chemistry by (60.3k points)
closed by
3 ampere current was passed through an aqueous solution of an unknown salt of Pd for 1 hour. 2.97 g of Pd was deposited at cathode. Find n. (At.wt. of Pd = 106.4)

1 Answer

0 votes
by (66.4k points)
selected by
 
Best answer
Correct Answer - 4
Since `Pd^(n+) +n e rarr Pd`
For `Pd, (w)/(E) = (ixx t)/(96500), (2.977)/(106.4//n) = (3 xx 1 xx 60 xx 60)/(96500) n = 4`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...