Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
57 views
in Chemistry by (78.7k points)
closed by
Purple of Cassius is obtained by the addition of `SnCl_(2)` solution to a solution of
A. `CuCl_(2)`
B. `HgCl_(2)`
C. `Hg_(2)Cl_(2)`
D. `AuCl_(3)`

1 Answer

0 votes
by (83.3k points)
selected by
 
Best answer
Correct Answer - D
`2Au^(3+)+3Sn^(2+)rarr2Au+3Sn^(4+)`. Au is adsorbed over `Sn(OH)_(4)` formed giving purple of Cassius.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...