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An inorganic sulphate on reaction with very dilute NaOH gave a precipitate which dissolved in excess of NaOH. The resultant dissolved in excess of NaOH. The resultant solution gave the sulphide of the metal when hydrogen sulphide gas was passed through it. The inorganic sulphate is
A. `MnSO_(4)`
B. `FeSO_(4)`
C. `NiSO_(4)`
D. `ZnSO_(4)`

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Correct Answer - D
`ZnSO_(4)+NaOH rarr Zn(OH)_(2) overset("Excess NaOH")(rarr)Na_(2)ZnO_(2)`
`Na_(2)ZnO_(2)+H_(2)S rarr Na_(2)S`

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