Correct Answer - B,D
(B) `[Cr (H_(2)O)+_(5)Cl]Cl_(2)+2AgNO _(3)to`
`2AgCl darr+[Cr(H_(2)O)_(5)Cl](NO_(3))_(2)`
`(M_(1)V_(1))/(n_(1))=(M_(2)V_(2))/(n_(2))`
`(0.01xx200)/(1)=(0.1xxV_(2))/(2)" "V_(2)=40ml`
(D) `[Cr(H_(2)O)_(4)Cl_(2)]Cl.H_(2)+AgMg to AgCl darr+[Cr(H_(2)O)_(4)Cl]AlSO_(3)H_(2)O`
`(M_(1)V_(1))/(n_(1))" "=(M_(2)V_(2))/(n_(2))`
`(0.01xx200)/(1)=(0.1xxV_(2))/(1)" "thereforeV_(2)=20 ml`