(b) The angle between the reflected ray and refracted ray
is `(120^(@)-theta)`.
For calclation of `theta`
`mu_(1)sini=mu_(2)sinr`
`1xxsin 60^(@)=sqrt(3)sin theta`
`(sqrt(3))/2=sqrt(3)sin theta`
`sin theta=1/2=sin 30^(@)`
`theta=30^(@)`
Hence `(120^(@)-30^(@))=90^(@)`